<span><span>16<span>x^4</span></span>+<span>40<span>x^3</span></span></span>−<span>24<span>x^<span>2
That is it</span></span></span>
4200ft divided by 20 ft per second divided by 60 seconds is 1400 minutes
Answer: Our required probability would be 0.9641.
Step-by-step explanation:
Since we have given that
Number of hours he works a day = 8
So, Number of minutes he worked in a day = 
Number of calls = 220
So, Average 
Standard deviation 
Mean = μ = 2.0 minutes
Standard deviation = σ = 1.5 minutes
Using the normal distribution, we get that

So, the probability that Albert will meet or exceed his quota would be

Hence, our required probability would be 0.9641.
Answer:
option (3) is correct.

Step-by-step explanation:
Given 
We have to solve for e.
Consider the given statement,

Cross multiply, we get,

Taking square root both sides , we get,

We know square root of 9 is 3.

Thus, option (3) is correct.
