Question

If it took Carlos 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 miles? (Note: 1 mile = 5280 ft)
(1) The average speed at which Carlos cycles from his house to the library yesterday was greater than 16 feet per second.
(2) The average speed at which Carlos cycles from his house to the library yesterday was less than 18 feet per second.

Answer 1

Answer:

Step-by-step explanation:

Given

time taken by Carlos to cycle is $t=0.5\ hr$

For case (1)

Average speed $v_{avg}>16\ ft/s$

For $0.5 hr \approx 30\times 60=1800\ s$

Distance traveled $d=1800\times 16=28,800\ ft\approx 5.45\ miles$

Therefore Carlos might not be able to cover 6 miles with average speed of  16 ft/s

(2)$v_{avg}=18\ ft/s$

for 0.5 hr

distance traveled

$d=1800\times 18=32,400\ ft\approx 6.136$

Therefore Carlos might be able to cover more than 6 miles with $18\ ft/s$