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kobusy [5.1K]
3 years ago
15

9. In the expression 4(2m-n), determine which of the following best describes the role of (2m-n).

Mathematics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

b

Step-by-step explanation:

2m is term because it is what you are looking for

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Your coffee bar has two kinds of drink One cup of the first one costs 9 grams of juice , 4 grams of coffee and 3 grams of sugar
VMariaS [17]

Answer:

How many drinks should be sold to get a maximal profit? 468

Sales of the first one = 345 cups

Sales of the second one = 123 cups

Step-by-step explanation:

maximize 1.2F + 0.7S

where:

F = first type of drink

S = second type of drink

constraints:

sugar ⇒ 3F + 10S ≤  3000

juice ⇒ 9F + 4S ≤  3600

coffee ⇒ 4F + 5S ≤  2000

using solver the maximum profit is $500.10

and the optimal solution is 345F + 123S

6 0
3 years ago
Triangle congruence worksheet
lesya [120]

Answer:

NC

Step-by-step explanation:

We know it is not SSS or AAS or ASA

On one triangle we have SAS but we don't see the same congruent markings so we cannot tell.

4 0
3 years ago
The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that
salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0
4 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Amiraneli [1.4K]
The side x is equal to 12
7 0
2 years ago
There are 1200 students at silver lake middle school 700 Are eighth graders what percent of the students are in the eighth grade
Leni [432]
(700/1200)*100 = 58.33%, rounding to the nearest 10th of à percent we get 60%
7 0
3 years ago
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