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3 years ago

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics

1 answer:

sashaice [31]3 years ago

7 0

Answer:

k = –10

Step-by-step explanation:

From the question given above, the following data were obtained:

f(x) = x³ – 6x² – 11x + k

Factor => x + 2

Value of K =?

Next, we shall obtained the value of x from x + 2. This is illustrated below:

x + 2 = 0

Collect like terms

x = 0 – 2

x = –2

Finally, we shall determine the value of k as illustrated below:

f(x) = x³ – 6x² – 11x + k

x = –2

Thus,

f(–2) = 0

x³ – 6x² – 11x + k = 0

(–2)³ – (–2)² – 11(–2) + k = 0

–8 – (4) + 22 + K = 0

–8 – 4 + 22 + K = 0

10 + k = 0

Collect like terms

k = 0 – 10

k = –10

Thus, the value of k is –10

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3 years ago

The line perpendicular to y= (-3/2)x -4 and goes through (1,4)

Paladinen [302]

Answer <u>(assuming it is allowed to be in point-slope format)</u>:

$y-4 = \frac{2}{3}(x-1)$

Step-by-step explanation:

1) First, determine the slope. We know it has to be perpendicular to the given equation, $y = -\frac{3}{2} x-4$ . That equation is already in slope-intercept form, or y = mx + b format, in which m represents the slope. Since $-\frac{3}{2}$ is in place of the m in the equation, that must be the slope of the given line.

Slopes that are perpendicular are opposite reciprocals of each other (they have different signs, and the denominators and numerators switch places). Thus, the slope of the new line must be $\frac{2}{3}$ .

2) Now, use the point-slope formula, $y-y_1 = m (x-x_1)$ to write the new equation with the given information. Substitute $m$ , $x_1$ , and $y_1$ for real values.

The $m$ represents the slope, so substitute $\frac{2}{3}$ in its place. The $x_1$ and $y_1$ represent the x and y values of a point the line intersects. Since the point crosses (1,4), substitute 1 for $x_1$ and 4 for $y_1$ . This gives the following equation and answer:

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3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

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Answer:

Step-by-step explanation:

Hello!

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Group 1 has 8 cows that receive the new feed + additive.

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After two weeks of feeding the animals with the different feeds, the production of milk of each group was recorded so that they can be compared.

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