3x - 2y = 5
2y = 3x - 5
y = (3/2) x - 5/2
so the gradient (m) of the required line = -1 / (3/2) = -2/3
using the general form
y - y1 = m(x - x1) , m = -2/3 , x1 = -2 and y1 = 1
y - 1 = -(2/3) ( x - (-2))
y = -(2/3)x - 4/3 + 1
y = -(2/3)x - 1/3
multiply through by 3
3y = - 2x - 1
in standard form its
2x + 3y = -1
(2x+9) + (10x+15) = 180°
2x+9 + 10x+15 = 180°
Add up liked terms
12x+24 = 180°
-24 on both sides
12x = 156°
/12 on both sides
x = 13
< ABC = (2x+9)
< ABC = 2(13)+9
Answer : < ABC = 35°
< CBD = (10x+15)
< CBD = 10(13)+15
Answer: < CBD = 145°
Answer:
lol same
Step-by-step explanation:
idek
Answer:
A line with a slope of – that passes through the point (–14, 4)
Step-by-step explanation:
The equation of a line is typically written as y= mx+b where m is the slope and b is the y- intercept.
Yes. As long as all four sides connect, it is a quadrilateral
