Question

Find the surface area of each prism. Round to the nearest tenth if necessary while doing your calculations as well as in your final answer.

Answer 1

Answer:

The answer is "340 units²"

Step-by-step explanation:

In the given question, an attachment file is missing, which can be defined as follows:

$\therefore \tan \theta= \frac{height}{base}\\\\\to \tan 60^{\circ}=\frac{h}{3}\\\\\to \sqrt{3}=\frac{h}{3}\\\\\to 3\sqrt{3}=h\\\\\to h = 3\sqrt{3} units$

The area of trapezoid prism:

$(a)= (b_1+b_2)h+ph$

value:

$b_1=6 \ units\\b_2=9 \units\\h=10 \ units\\\\\to P=6+9+3\sqrt{3}+\sqrt{3^2+(3\sqrt{3})^2}\\\\\to P=15+3\sqrt{3}+\sqrt{9+27}\\\\\to P=15+3\sqrt{3}+\sqrt{36}\\\\\to P=21+3\sqrt{3} \ unit\\\\\bold{ Area= (6+9) \times 3\sqrt{3}+(21+3\sqrt{3})\times 10}\\\\\to Area= (15) \times 3\sqrt{3}+(21+3\sqrt{3})\times 10\\\\\to Area= 45\sqrt{3}+210+30\sqrt{3}\\\\\to Area=339.9038\\\\\to Area=340 \ units^2$