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netineya [11]
3 years ago
11

What two whole square root numbers are between 54

Mathematics
2 answers:
NARA [144]3 years ago
5 0

The space between a single point is undefined.  It's like the
sound of one hand clapping, or one scissor, or a single pant.


Over [174]3 years ago
4 0
There are square roots of 1,4,9,16,25,36, and 49 between 54, just choose 2 
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Megan received a $208,000 inheritance after taxes from her parents. She invested it at 8% interest compounded quarterly for 5 ye
Nookie1986 [14]
Use the compound interest formula.
  A = P*(1 +r/n)^(n*t)
where P is the principal, r is the annual rate, n is the number of compoundings per year, and t is the number of years.

For the first investment, ...
  A = 208,000*(1 +.08/4)^(4*5) = 309,077.06

For the second investment, ...
  A = 218,000*(1 +.07/2)^(2*4) = 287,064.37

Totaling both investments at maturity, Megan has $596,141.43.
3 0
4 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
Given f(x)= -x+15, what is f(-3) A.-45 B.12 C.18 D.45
lina2011 [118]
So you just subsitute -3 for x
f(-3)=-(-3)+15
f(-3)=3+15
f(-3)=18
answer is C
18
8 0
3 years ago
18m-9v+6v-7m hope you can help
Valentin [98]
Here, you have to combine like terms. So, it is 11m-3v.
7 0
3 years ago
Read 2 more answers
A soccer team made 76 penalty shots out of 100.Which ratio represents successful penalty shots to missed penalty shots?
almond37 [142]
Sense we are wanting to find <u>how many were miss</u>, then, we are practically going to subtract the following:

\boxed{76-100}= \     \left[\begin{array}{ccc}\bf{24\end{array}\right]

So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.

So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.

Your answer: \boxed{\bf{76:24}}
5 0
3 years ago
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