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goldfiish [28.3K]

2 years ago

8

Whats .0196 to the nearest thousandths

1 answer:

lana66690 [7]2 years ago

5 0

The answer is 0.200 because when you are rounding, normally you have to see if the number next to the number you are supposed to be rounding to is 4 or under or 5 or over. If the number is 4 or under, you round down and if the number is 5 or over then you round up. So since 9 is in the thousandths place and the number next to it is 6, then you round up and make the entire decimal 0.200.

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The question is in the picture

yawa3891 [41]

Answer: May you show the angle we are supposed to solve? its a bit unclear. or can you explain the angle to us?

Step-by-step explanation:

6 0

3 years ago

What is the slope intercept form of the equation of the line

Vlad [161]

The answer is C, your b in the equation is 4, and your slope is 1/2. Starting from four, you move up one and right two which means the slope is 1/2.

6 0

2 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

2 years ago

What is the area of the figure?

Vanyuwa [196]

Answer: 42.5 m

Step-by-step explanation:

Split the figure into a rectangle and a triangle.

Find the areas of the rectangle and the triangle seperately and add them together.

Rectangle: 7 x 5 = 35

Triangle: 5 x 3/2 = 7.5

35+7.5= 42.5m

8 0

2 years ago

Read 2 more answers

What is 8 diveded by 3

Sophie [7]

Answer:

2.66666666667

Step-by-step explanation:

2.6666666667x3=8

5 0

2 years ago