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3 years ago

Choose the correct description of the graph of the inequality x − 3greater than or equal to 5

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Not sure what the correct description is but the answer is:
x ≥ 8

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What is the approximate area of a circle with a radius of 10 in?

yKpoI14uk [10]

$\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}$

Correction to your question text: diameter, not radius.

The area of a circle is given by:

$A=\pi r^2$

The radius is half of the diameter.

$A=\pi\cdot\left(\dfrac{10}{2}\right)^2$

Substitute and solve.

$\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}$

5 0

2 years ago

Could someone please help answer this (homework help) will give brainliest, please no spam, thank you!

Nitella [24]

Answer:

m= 4(25) + 2(7)

m= 100 + 14

m= 114

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3 years ago

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

3 years ago

Region R is bounded by the curves y = 4x2 and y = 4. A solid has base R, and cross sections perpendicular to the y-axis are semi

natulia [17]

Answer:

Step-by-step explanation:

12+22=69

5 0

3 years ago

What's 1 + 1 ? I need 5 lines of steps tyvm

GREYUIT [131]

$1+1\\\\= 1+1\\\\=1+1\\\\=1+1\\\\=2$

3 0

2 years ago

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