The standard quantity of metal per ring is 0.57 kilograms.
Step-by-step explanation:
Each ring requires 0.52 kilograms of a special metal.
The allowance for waste is 0.03 kilograms per ring, while the allowance for rejects is 0.02 kilograms per ring.
So, the standard quantity of metal per ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)
= 
kilograms.
Hence, the standard quantity of metal per ring is 0.57 kilograms.
Answer:
No solutions
Step-by-step explanation:
Substitute 3^x with t and we get.
Answer:the length of the shorter string= 36cm
Step-by-step explanation:
Let us assume the lengths are 2x and 7x since thery are in the ratio of 2 :7
Such that Length of the shorter string = 2x
and the longer string = 7x so that the difference in Length which is 90cm can be expressed as
7x- 2x= 90
5x= 90
x 90/5
x= 18
shorter string = 2 x = 2x 18= 36cm
Longer strring = 7x 18=126cm
Remember, you can do anything to an equation as long as you do it to both sides
and when multiply or divide by a negative in inequalities, flip the direction of the sign
12x-39<9
add 39 to both sides
12x<48
divde bothh sides by 12
x<4
-4x+3<-6
minus 3 both sides
-4x<-9
times both sides by -1 and flip sign
4x>9
divide both sides by 4
x>9/4
