If (7^0)^x = 1, what are the possible values of x?

1 answer:

5 0

(7^0)^x = 1

7 power zero is 1.

(1^x) = 1

So x can be any value.

x could be, -2, -3, 1, 0, 3, 5, 1.8, -1.5,

x could be any number positive or negative or even zero.

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Which of these ordered pairs is the best estimate of the solution of the system y = 3x + 2 and y = -1/4 x + 1?

Lelu [443]

If the solution exists, y=y....

3x+2=-x/4+1 make everything have a common denominator of 4...

(12x+8)/4=(-x+4)/4 now multiply both sides by 4

12x+8=4-x add x to both sides

13x+8=4 subtract 8 from both sides

13x=-4 divide both sides by 13

x=-4/13

x≈-0.31 and the only pair in your choices having an x value close to that is:

(-0.3, 1.1)

6 0

3 years ago

Please help work this equation

Flauer [41]

Hi!

<u>Given these two equations:</u>

$x = y + 8$

$x + 4 = 2(y + 4)$

We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:

$(y+8)+4=2(y+4)$