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lana66690 [7]
3 years ago
8

The dramatic growth in the number of power data centers, cell towers, base stations, recharge mobiles, and so on is damaging the

environment because many of these new technologies have been located in fragile or important natural environments, putting the ecosystem at risk.
A. True
B. False
Engineering
1 answer:
Elis [28]3 years ago
7 0

Answer:

True

Explanation:

The statement is true because power data centers, cell towers, base stations, recharge mobiles, and so on emit electromagnetic waves which radiate to the space and causes ozone layer depletion which are harmful to both planet and human in such that it damage the ecosystem and release of ultraviolet rays causes skin cancers in human living in the environment.

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Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a
Katyanochek1 [597]

Answer:

K_{I}=5.21 MPa\sqrt{m}

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}   ................................1

here Y is the geometrical function

so

Y = \frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}

Y = \frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}  

Y = \frac{0.8792}{0.89}  

Y = 0.9878

so put here value in equation 1

K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}    

K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319

K_{I} = 5210.45 × 10³  Pa\sqrt{m}  

K_{I} = 5.21 MPa \sqrt{m}

5 0
3 years ago
What major risk does a company take when it decides to compromise quality for cost?
icang [17]

Answer:

honestly i don't know ok and you are pretty if that is you in the pfp

Explanation:

3 0
3 years ago
Read 2 more answers
A cylindrical rod of a metal alloy is stressed elastically in tension. The original diameter was 11 mm and a force of 55 kN was
andrey2020 [161]

Answer:

10.984mm

Explanation:

by elastic modulus

stress=modulus of elasticity*strain

stress=loading/area                          area" cross-section"

11mm=0.011m

area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter

stress=55000/(9.503*10^-5)=578.745 MPa

convert MPa and GPa to pascal.

strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain

v=Poisson  ratio

lateral strain=(-v)*axial strain= -0.31*0.00463

lateral strain= -1.4353*10^-3=change in diameter/ original diameter

change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m

negative indicates decrease in diameter.

decrease in dia.=0.01578mm

new diameter=11-0.01578= 10.984mm

3 0
3 years ago
Project 13.3: Assessing Risk Management According to the FFIEC Information Security InfoBase Handbook ( Appendix A ), the initia
Rashid [163]

Answer:

1. Changes in network topology or system configuration might bring security-related challenges. For example, adopting a new system configuration which is low in cost but also very new in the Industry might be vulnerable to the existing security.

2. New products or Services which are delivered to either the Internal/External users might be prone to security issues.

Let say a product 'A' has been launched by a company 'X' and for testing purpose it has been given to the internal users. Now as this product 'A' is a product of 'X' itself it will be allowed to carry in the official premises and if some user tries to hack this product and can make the product potentially harmful w.r.t security.

3. Consider a scenario where there is a change in management & team, the team members which were thoroughly responsible for Security kinds of stuff are dissolved into different teams. Also new members are hired for the team. Now, since the new members will need some time to get adapted to the Business As Usual things there are high chances of a security level not maintained as it was earlier by the old guys. This could be due to undocumented things in the organization or due to lack of Knowledge Transfer to the new joinees.

5 0
3 years ago
You are adjusting pH in the fed-batch bioreactor using a 1.5 Molar solution of Ca(OH)2 (Assume that in given conditions the base
mrs_skeptik [129]

Answer:

Final osmolarity = 866 mOsm

Explanation:

Starting cell culture medium = 320 mOsm

30 mL of 1600 mM NaOH into 1 L= (30 mL/1000) x 1600 = 48 mM

Osmolarity = osmoles / 1 L = (Mole x equivalent) / L = 48 x 2 = 96 mOsm

Feed solution = (300 mL / 1000 mL) 1500 mOsm = 450 mOsm

Total osmolarity = 320 + 96 + 450 = 866 mOsm

Hope this helps!

3 0
3 years ago
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