Answer:
The size of equalization basin is 6105.6 m³
Explanation:
The average flow is:
flow = ∑flow/n = 9.788/24 = 0.408 m³/s
Where n is the number or observations.
The inflow volume is:
where t is the time interval
in the same way it is calculated the inflow volume for each observation
The outflow volume is:
The volume of flow is:
in the same way it is calculated the volume of flow for each observation. According to the file attach, the highest volume is 6105.6 m³
Answer:
c from transmitter to a receiver
Answer:
The Civil-Military Operations Center (CMOC).
Explanation:
The Civil-Military Operations Center (CMOC), currently recognized in joint operation, emerges as the most appropriate structure for the planning, coordination, execution, and assessment of civil-military activities. The center should be strategically located to serve its purpose.
Answer:
Time delay increases
Explanation:
Time delay is the delay between occurance of signal. If sampling time that is time between two samples is increased, the delay in the occurance of regenerated samples is also increased.
Answer: 12.4 feet
Explanation:
If there is a smooth transition and there is no change in slopes, energy considerations can be used
The cube has a kinetic energy of
ke = mv^2/2 = 10 lbm * 20^2ft^2/s^2 / 2 = 2000 lbm-ft^2 / s^2
At the highest point when there is a gain in potential energy
pe = mgh = 10 lbm * 32.2 ft/s^2 * h ft = 322 lbm ft^2/s^2
If there is no loss in energies,
pe = ke
322h lbm ft^2/s^2 = 2000 lbm ft^2/s^2
h = 2000 /322 = 6.211 (ft)
= h / sin(30) = 12.4 ft