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AfilCa [17]
3 years ago
14

The brakes are being bled on a passenger vehicle with a disc/drum brake system. Technician A says that the drums should be remov

ed before bleeding. Technician B says that the fluid in the master cylinder should be kept low during the bleeding procedure. Who is right?
Engineering
1 answer:
exis [7]3 years ago
4 0

The brakes are being bled on a passenger vehicle with a disc/drum brake system is described in the following

Explanation:

1.Risk: Continued operation at or below Rotor Minimum Thickness can lead to Brake system failure. As the rotor reaches its minimum thickness, the braking distance increases, sometimes up to 4 meters. A brake system is designed to take kinetic energy and transfer it into heat energy.

2.Since the piston needs to be pushed back into the caliper in order to fit over the new pads, I do open the bleeder screw when pushing the piston back in. This does help prevent debris from traveling back through the system and contaminating the ABS sensors

3.There are three methods of bleeding brakes: Vacuum pumping. Pressure pumping. Pump and hold.

4,Brake drag is caused by the brake pads or shoes not releasing completely when the brake pedal is released. ... A worn or corroded master cylinder bore causes excess pedal effort resulting in dragging brakes. Brake Lines and Hoses: There may be pressure trapped in the brake line or hose after the pedal has been released.

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Why do engineers play a variety of roles in the engineering process? They are part of a team. They need to act as both scientist
Kamila [148]

Answer: They showed that many people worked on the project and demonstrate how hard they worked.

Explanation:

4 0
3 years ago
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6. When the engine stalls or the power unit fails, on a car with power
frutty [35]
B

But

I think

So yea it prob isn’t
3 0
3 years ago
A screw extruder is 50 mm in diameter, 1 m long, has a 50mm lead, a channel 5 mm deep and a flight 3 mm wide. The circular die t
Margarita [4]

Answer:

A) 105.7 rpm

B) 11.32 kw

C) 20.85 NPa

Explanation:

Number of solid rods to be manufactured = 3600

<u>a) Determine the RPM of the screw</u>

we will apply the relation below

discharge rate ( Qd ) = 0.5 π^2 * D^2 * N di * sinA * cos A  ------- ( 1 )

where : D = 50 mm , di = 5 mm , N = ?

Tan A = p / πD = 50 / π*50 ∴ A = 17.65°

Insert values into equation ( 1 )

Qd = 17.83 * 10^-6 * N

required discharge rate ( Q ) =  \frac{\frac{\pi D^2}{4}*L*N }{Time}   ------ ( 2 )

where : D = 0.01 , L = 25 * 10^-2 , N = 3600 , time = 10 * 3600

input value into 2

Q = 31.415 * 10^-6 m^3/s

<em>Hence the RPM of the screw ( N )</em>

= Q / Qd =  31.415 * 10^-6 / 17.83 * 10^-6  = 1.76 rev/s = 105.7 rpm

<u>b) Determine the power requirements of the extruder</u>

max power requirement  = Pm * A * πDN / 60

                                         = ( 20.85 * π * ( 50 )^2 / 4 ) * π * 150 *1.76

max power requirement = 11.32 kw

<u>c) What is the pressure buildup within the extruder</u>

Pressure buildup within the extruder  = ( 6π*D*N*L* η * cot A ) / di^2  

= ( 6π * 0.05 * 1.76 * 1 * 100 * cot17.65 ) / ( 5 * 10^-3 )^2

therefore ; Pm = 20.85 NPa

3 0
3 years ago
Chaplets are used to support a sand core inside a sand mold cavity. The design of the
ziro4ka [17]

Answer:

a) 2 chaplets

b) 9 chaplets

Explanation:

Before we can determine the minimum number of chaplets that should be placed beneath and above the core, we must know the mass of the sand used to make the surface of the mold cavity as well as the mass of the steel metal poured inside the mold.

Density is defined as the ratio of mass of a substance to its density.

Density = Mass/Volume

For the STEEL:

Density of steel = 7.82g/cm³

Volume = volume of the core = 5450cm³

Mass = Density × Volume

Mass of steel = 7.82×5450

Mass of steel = 42619g

Mass of steel in kg = 42.619kg

For the SAND:

Density of sand = 1.6g/cm³

Volume = volume of the core = 5450cm³

Mass = Density × Volume

Mass of sand = 1.6×5450

Mass of sand = 8720g

Mass of sand in kg = 8.72kg

a) Since the the chaplet support the sand from beneath the core, and each chaplet weighs 45N, we need to know the amount of force possessed by the sand.

Since the mass of the sand is 87.2kg

Weight = mass × acceleration due to gravity

Weight = 8.72×9.81

Weight of sand used to mold the core = 85.54N

Since 1 chaplet weighs 45N

This means that (85.54N/45N) i.e 1.9 which is approximately 2 chaplets must be placed beneath the core to sustain it before the steel metal is poured.

b) Since the metal poured in the core is steel, this means that the chaplet placed above the core must be able to withstand the strength of the steel.

Weight of steel = mass of steel × acceleration due to gravity

Weight of steel = 42.619×9.81

Weight of steel = 418.09N

Since one chaplet weigh 45N, the amount of chaplets that must be placed above the core is;

418.09/45

= 9.3

Therefore the minimum number of chaplets that should be placed above the core after pouring steel metal is 9chaplets.

4 0
3 years ago
A city has a population of 50,000 people, an average household generated wastewater flow of 430 L/day-person, and the average BO
Andrew [12]

Answer:

The ultimate BOD of waste water is 265 milligram per Liter.

Explanation:

To start with and properly determine the ultimate BOD of the waste water, we need to determine the volume of water used by the population in the city within five days.

Therefore,   50000 people × 430 Liters ÷ day-person × 5 days

1.08 × 10∧8 Liters

The mass BOD5 by the city population in 5 days is therefore,

0.1 kilogram ×  BOD5 ÷ day-person × 50000 people × 5 days

2.5 × 10 ∧ 4 BOD5

The 5 days BOD of waste water is therefore,

5d = 2.5 × 10 ∧ 4 / 1.08 × 10 ∧ 8 Liters × 1000grams  ÷ 1 kilogram × 1000mg ÷ 1gram

233 milligram / liter

The ultimate BOD, is therefore,

ULo = 5d ÷ (1 - e ∧ -k5)

Solving this further, we derive

265 milligram per Liter.

7 0
3 years ago
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