Step-by-step explanation:
L.H.S=(1-cosB)(1+cosB)
=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}
=sin^2B
=1/cosec^2B
Therefore,L.H.S=R.H.S proved
If f(1) =5-2(1)
F(2)=5-2(2)
The answer is n equals five
Answer:
The radius of the inner circle is 14 ft. Since the outer circle is 3 ft more than the inner circle, its radius is 17 ft. The circumference formula is 2(pi)radius (or 2(22/7)17 in this case). The circumference of the outer circle is 106.85 ft (or 106.9 if rounding). To find the difference, you would subtract the smallest FROM the greatest:
106.85 - 88 = 18.85 ft (or 18.9 if rounding)
