Every possible cross section of a three-dimensional figure is a circle. What is the figure?

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

5 0

Answer:

its cylinder

Step-by-step explanation:

dsp733 years ago

3 0

A cross section is the shape we get when cutting straight through an object. In geometry it is the shape made when a solid is cut through by a plane. cylinder cross section.The cross section of this circular cylinder is a circle.

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A football field is a rectangle 80 meters wide and 110 meters long. Coach Trevor asks his players to run from one corner to the

vladimir2022 [97]

Answer: the distance from one corner of the field to the other corner is 136 m

Step-by-step explanation:

The distance from one corner to the other corner is the diagonal and it

divides the field into two equal right angle triangles. The diagonal represents the hypotenuse of each right angle triangle. The length and width of the rectangle represents the adjacent and opposite sides of the right angle triangle. To determine the length of the diagonal, d, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore

d² = 110² + 80²

d² = 12100 + 6400 = 18500

d = √18500

d = 136 meters

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3 years ago

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Whitepunk [10]

Answer: the answer is d

Step-by-step explanation:

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tatiyna

Her profit was around the amount of $7-$52

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3 years ago

The circular stream of water from a faucet is observed to taper from a diameter of 20 mm to 10 mm in a distance of 50 cm. Determ

steposvetlana [31]

Solution:

From Bernoulli equation

$\frac{1}{2}$ ρ $V_{1}^{2}$ + ρgh = $\frac{1}{2}$ ρ $V_{2}^{2}$ , where ρ is density of water, h – height difference and $V_{1}$ and $V_{2}$ are the velocities in upper and lower cross sections correspondingly. We take into account that the pressure in both cross-sections is the same and equal to the atmospheric one.

From the continuity and assuming water incompressible:

$\pi r_{1}^{2}$ $V_{1}$ = $\pi r_{2}^{2}$ $V_{2}$ , where $A_{1}$ and $A_{2}$ are the corresponding cross-sections. As the lower diameter is twice as low as the upper one, we can conclude that $V_{1} = \frac{V_{2}}{4}$