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3 years ago

Answer ASAP pleaseeee !!!!

Mathematics

2 answers:

vivado [14]3 years ago

6 0

The answer is 6.3. 6.3 squares is 39.69 which rounds to 40

Eddi Din [679]3 years ago

3 0

x=8.9 because when you square it and divide you get 39.6.. rounded to 40.

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Given a force of 10N and an acceleration of 5m/s? What is the mass?

likoan [24]

Answer:

Step-by-step explanation:

Mass is a body of matter without definite shape.

Use the Newton's second law of motion formula.

Note: $\longrightarrow \sf{F=M*A}$

<u>Given:</u>

Force = 10N
Acceleration = 5m/s

First thing you do is divide.

10/5=2

= 2kg (mass)

Therefore, the final answer is 2kg (mass).

I hope this helps, let me know if you have any questions.

To learn more about the mass:

brainly.com/question/7580108

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1 year ago

To solve y and x, I am adding a picture

Viktor [21]

Answer:

$x =\sqrt 5$

$y = \sqrt{5$

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

$\cos(45) = \frac{y}{\sqrt{10}}$ --- cosine formula i.e. adj/hyp

Solve for y

$y = \sqrt{10} * \cos(45)$

In radical form, we have:

$y = \sqrt{10} * \frac{1}{\sqrt 2}$

$y = \sqrt{10/2}$

$y = \sqrt{5$

To solve for x, we make use of Pythagoras theorem

$x^2 + y^2 = (\sqrt{10})^2$

$x^2 + y^2 =10$

Substitute for y

$x^2 + (\sqrt 5)^2 =10$

$x^2 + 5 =10$

Collect like terms

$x^2 =10-5$

$x^2= 5$

Solve for x

$x =\sqrt 5$

4 0

2 years ago

If f(x)=5x, what is f^-1(x)?

Georgia [21]

Answer:

first thing to do is get up from your sit and go cry because that question is to hard

5 0

3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

2 years ago

Write the complex number in the form a + bi.<br> 3(cos 60° + i sin 60°)

hram777 [196]

Answer:

The complex number in the form of a + b i is 3/2 + i √3/2

Step-by-step explanation:

* Lets revise the complex number in Cartesian form and polar form

- The complex number in the Cartesian form is a + bi

-The complex number in the polar form is r(cosФ + i sinФ)

* Lets revise how we can find one from the other

- r² = a² + b²

- tanФ = b/a

* Now lets solve the problem

∵ z = 3(cos 60° + i sin 60°)

∴ r = 3 and Ф = 60°

∵ cos 60° = 1/2

∵ sin 60 = √3/2

- Substitute these values in z

∴ z = 3(1/2 + i √3/2) ⇒ open the bracket

∴ z = 3/2 + i √3/2

* The complex number in the form of a + b i is 3/2 + i √3/2

6 0

2 years ago

Read 2 more answers