Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
Answer:
17zy
Step-by-step explanation:
big brain
Answer:
-127.488°
Step-by-step explanation:
45" is 0.75 of 1', so -128° 30' 45" = -128° 30.75'
Next: 30.75' is 30.75/60 of 1°, and or -128° plus 0.5125 of 1°.
The final answer is found by adding 0.5125° to -128°:
-128.0000°
+ 0.5125°
--------------------
-127.4875
To the nearest thousandths of a degree, that would be -127.488°
we have
------> inequality A
The solution of the inequality A is the shaded area below the solid red line
see the attached figure N
------> inequality B
The solution of the inequality B is the shaded area above the dotted blue line
see the attached figure N
therefore
The solution of the system of inequalities is the shaded area between the solid red line and the dotted blue line
see the attached figure N
therefore
the answer in the attached figure N
