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Zepler [3.9K]
4 years ago
6

Help me solve the problem please

Mathematics
1 answer:
Lady_Fox [76]4 years ago
8 0

Answer:

The answer is (2, 0)

Step-by-step explanation:

Plug in the (x, y) values for both inequalities from each answer choice. When you do that, only one option, (2, 0), will result in a false statement.

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Simplifying Complex fractions using any method
zloy xaker [14]

Answer:

3ab

-------------------

(b+a)

Step-by-step explanation:

3/a - 3/b

-------------------

1/a^2 - 1/b^2

Multiply the top and bottom by a^2 b^2/ a^2/b^2 to clear the fractions

(3/a - 3/b) a^2 b^2

-------------------

(1/a^2 - 1/b^2) a^2b^2

3ab^2 - 3 a^2 b

-------------------

b^2 -  a^2

Factor out 3ab on the top

3ab( b-a)

-------------------

b^2 -  a^2

The bottom is the difference of squares

3ab( b-a)

-------------------

(b-a) (b+a)

Cancel like terms from the top and bottom

3ab

-------------------

(b+a)

6 0
3 years ago
Read 2 more answers
What is the ordered pair after this point is reflected across the y-axis? 4,2
Zepler [3.9K]

Answer:

-4,2

Step-by-step explanation:

a reflection across the y axis means the y values stay the same and the x values change sign

8 0
3 years ago
Mrs. Walters drove 360 miles on 25 gallons of gas. Mr. Walters drove 480 miles on 32 gallons of gas.
Temka [501]

Answer:

Mr.Walters car can go 15 miles on one gallon of gas.

Step-by-step explanation:

To find this, you first want to put it into a ratio.

480:32

Next, you want to divide.

480/32

After you divide, you get 15. That tells you that you get 15 miles off of one gallon of gas.

8 0
3 years ago
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REUPLOAD! Could you help me with these questions? They are solving and listing 1 of 4 properties. Please don't waste my points.
daser333 [38]

Answer:

First columns distributive property 14xy and 48z

5 0
3 years ago
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For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is direct
Mrrafil [7]

THe problem is basically telling us: P=kV^2

where P is the power disappated and V^2 is our voltage squared.

\frac{1}{16}=k*14^2\implies\\ \frac{1}{16*196}=k \implies \\ \frac{1}{3136}=k

So, for the second example to find the power we simply have to plug k and our voltage back in, so:P=\frac{14^2*3^2}{14^2*6} \implies \\ P=\frac{9}{6}= \frac{3}{2}

6 0
3 years ago
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