2 years ago

This is part two of the problem

Mathematics

2 answers:

nadezda [96]2 years ago

6 0

Answer:

Area original = 8

Area new = 24

Area final = 3 x area original

True

Step-by-step explanation:

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

uranmaximum [27]2 years ago

5 0

Answer:

a) original: 8

final: 24

b) 3

c) true

Step-by-step explanation:

You might be interested in

What is the mean absolute deviation for 2,9, 1, 7, 8, 9

Phantasy [73]

Answer:

3 :)

Step-by-step explanation:

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B12x%7D%7B2x-3x-10%7D%20-%20%5Cfrac%7Bx%7D%7B%28x-5%29%7D" id="TexFormula1" title="\f

uysha [10]

Answer:

Step-by-step explanation:

$\frac{12x}{2x-3x-10}-\frac{x}{x-5}=\frac{12x}{-x-10}-\frac{x}{x-5}\\\\=\frac{12x}{-(x+10)}-\frac{x}{x-5}\\\\=\frac{-12x}{x+10}-\frac{x}{x-5}\\\\=\frac{-12x*(x-5)}{(x+10)*(x-5)}-\frac{x*(x+10)}{(x-5(x+10)}\\\\=\frac{-12x*x-5*(-12x)}{(x+10)(x-5)}-\frac{x*x+x*10}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x}{(x+10)(x-5)}-\frac{x^{2}+10x}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x-(x^{2}+10x)}{(x+10)(x-5)}\\\\=\frac{-12x^{2} + 60x - x^{2}-10x}{x^{2}+5x-50}\\\\=\frac{-13x^{2}+50x}{x^{2}+5x-50}$