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3 years ago

What else would need to be congruent to show that abc = def by sas?

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

7 0

Answer:

(A)AC=DF is correct

Step-by-step explanation:

It is given that AB=DE and ∠A=∠D and we have to prove ΔABC≅ΔDEF, then

From ΔABC and ΔDEF, we have

AB=DE(given)

∠A=∠D(given)

AC=DF (because given triangles are congruent)

Thus, by SAS rule, ΔABC≅ΔDEF

Therefore, in order to prove that ΔABC≅ΔDEF by SAS rule, we need AC≅DF.

Thus, option A is correct.

8090 [49]3 years ago

4 0

Because you know that A and D are equal and AB and DE are equal, the answer would be A.

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3 years ago

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frutty [35]

Answer:8-oz jar

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8 0

3 years ago

Read 2 more answers

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$