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Nesterboy [21]
3 years ago
5

If tanx=-4/3 and x is in quadrant 2 then cos2x=? A. 7/25 b. -3/5 c. -7/25 d. 3/5

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

= (1 - tan^2 (x)) / (1 + tan^2 (x))  

= (1 - (-4/3)^2) / (1 + (-4/3)^2)  

= (1 - (16/9)) / (1 + (16/9))  

= (9 - 16) / (9 + 16) [By multiplying numerator and denominator with 9]  

= (-7) / (25)  

= -7/25

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50 degrees C

Step-by-step explanation:

5/9(F-32)

5/9=.55555556

(122-32)=90

90×.555555556=50

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16.4.57 Question Help A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill You bl
Rudiy27

Answer:

$ 7.7

Step-by-step explanation:

Given,

There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,

Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus,

The probability of $ 1 = \frac{18}{40}

The probability of $ 5 = \frac{10}{40}

The probability of $ 10 = \frac{8}{40}

The probability of $ 20 = \frac{3}{40}

The probability of $ 100 = \frac{1}{40}

If a bill is selected randomly,

The expected value of the bill

=\frac{18}{40}\times 1+\frac{10}{40}\times 5+\frac{8}{40}\times 10+\frac{3}{40}\times 20+\frac{1}{40}\times 100

=\frac{18+50+80+60+100}{40}

=\frac{308}{40}

= $ 7.7

5 0
3 years ago
IM CONFUSED AGAIN- i hate math
allochka39001 [22]

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What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0
3 years ago
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