The data set below shows the weights of some puppies, in pounds, at a kennel:

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

The answer is

D. A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 4, the bar for the second range goes to 2, the bar for the third range goes to 3.

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valentinak56 [21]3 years ago

3 0

Answer:

D. A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 4. The bar for the second range goes to 2, the bar for the third range goes to 3.

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Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x

Cerrena [4.2K]

First, we are going to use the Pythagorean identity: $sin^2(x)+cos^2(x)=1$ to rewrite our expression. Solving for $sin^2(x)$ in our Pythagorean identity we get that $sin^2(x)=1-cos^2(x)$ , so we can rewrite our expression as follows:
$\frac{1}{ \sqrt{1-cos^2(x)} } = \frac{1}{ \sqrt{sin^2(x)} } = \frac{1}{sin(x)}$

Next, we are going to use the trig identity: $csc(x)= \frac{1}{sin(x)}$ to completely simplify our expression:
$\frac{1}{sin(x)} =csc(x)$

We can conclude that $\frac{1}{ \sqrt{1-cos^2(x)} }=csc(x)$