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2 years ago

Find the value of tanθ, if cosθ = 4/5 ; 0° ≤ θ< 90°

Mathematics

1 answer:

Montano1993 [528]2 years ago

4 0

Answer:

Step-by-step explanation:

Given

cosθ = 4/5
0° ≤ θ < 90°

In the first quadrant both sine and cosine are positive, so as tangent.

tanθ = sinθ / cosθ =
$\sqrt{1 - cos^2}$ θ / cosθ =
$\sqrt{1 - (4/5)^2}$ / 4/5 =
$\sqrt{9/25}$ / 4/5 =
3/5*5/4 =
3/4

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Find the value of tanθ, if cosθ = 4/5 ; 0° ￼￼≤ θ< 90°￼

Find the value of tanθ, if cosθ = 4/5 ; 0° ≤ θ< 90°