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horrorfan [7]
3 years ago
5

A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along

the surface?
Physics
2 answers:
kolezko [41]3 years ago
5 0
First, we calculate for the weight of the object by multiplying the given mass by the acceleration due to gravity which is equal to 9.8 m/s²
                       Weight = (14 kg)(9.8 m/s²)
                          Weight = 137.2 N
The component of the weight that is along the surface of the inclined plane is equal to this weight times the sine of the given angle. 
                         Weight = (137.2 N)(sin 52°)
                               weight = 108.1 N
madreJ [45]3 years ago
3 0

Answer:

108 N rounded

Explanation:

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