A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along
2 answers:
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To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is s=r(B), that has its <span>r=radius,B=angle in rad
velocity v=ds/dt= w(r)
Do not forget about </span> w = angular speed in rad/s and
Now we can go to proportion
SOLVING FOR A :
or something about <span>10 mph --- SOLVING FOR B.
</span>I'm sure it helps!
Do not forget about </span> w = angular speed in rad/s and
Now we can go to proportion
SOLVING FOR A :
</span>I'm sure it helps!
Answer:
K = 960 J
Explanation:
Given that,
Mass of a child = 20 kg
Mass of a sled = 10 kg
Speed of child on sled = 8 m/s
We need to find the kinetic energy of the sled with the child.
The total mass of child and the sled = 20 kg + 10 kg
= 30 kg
The formula for the kinetic energy of an object is given by :
Hence, the kinetic energy of the sled with the child is 960 J.