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2 years ago

The equatorial diameter of venus is 7,523 miles. if a mile equals 1.609 km, what is venus's diameter in kilometers?

Physics

1 answer:

polet [3.4K]2 years ago

6 0

The diameter of venus in km is 12104.507Km.

<h3 /><h3>What is Unit conversion?</h3>

By definition, unit conversion refers to the division or multiplication operation used to convert measurements of the same quantity between various units. The act of converting something from one form to another in mathematics, such as from inches to millimetres or from litres to gallons, is known as conversion.

the diameter of venus = 7,523 miles

1 mile = 1.609 km

so,

diameter of venus = 7523 × 1.609 Km

= 12104.507Km

to learn more about unit conversion go to - brainly.com/question/13016491

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What is 5kg fall from 2.1 meter using g=9.8m/s

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Answer:

103.J

Explanation:

Given data

Mass= 5kg

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8 0

3 years ago

Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce

Elena L [17]

Answer:

The value is $\lambda = 900 \ nm$

Explanation:

From the question we are told that

The width of the slit is $a = 0.15 \ mm = 0.00015 \ m$

The distance of the screen from the slit is D = 1.25 m

The width of the central maximum is $y = 0.75 \ cm = 0.0075 \ m$

Generally the width of the central maximum is mathematically represented as

$y = \frac{m * D * \lambda}{a}$

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima

$\lambda = \frac{a y}{ m * D }$

=> $\lambda = \frac{ 0.000015 * 0.0075}{ 1 * 1.2 }$

=> $\lambda = 900 *10^{-9} \ m$

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6 0

3 years ago

please explain!! 15. You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s2 for acceleration d

qwelly [4]

I will be making the assumption that you aren't actually really throwing the object over a bridge but rather dropping it as no initial velocity is actually given, which is required to do this problem. This will mean that initial velocity will be zero in this case.

First off, let's state all of the information we are given (the five kinematic quantities)

v₁ = 0 m/s

v₂ = cannot be determined

Δd = ?

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Now analyzing what we have, we can determine that we have 3 given quantities, 1 we must solve for, and 1 that cannot be found given our current information.

The five kinematic equations are useful because they all contain four kinematic quantities, and with different combinations too. In this case, we have three (v₁, Δt, a) and have to solve for Δd. The kinematic equation that fits with this would be:

Δd = v₁Δt + 0.5(a)(t)²

We can plug in our given values now.

Δd = 0 m/s(8 s) + 0.5(10 m/s²)(8 s)²

Δd = 0.5(10 m/s²)(8 s)²

Δd = <u>3</u>20 m

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3 years ago

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lubasha [3.4K]

Hi there!

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2 years ago

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salantis [7]

Answer:

The length of the simple pendulum is 2.4 meters.

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L = 2.4 m

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3 years ago