Answer:
The natural frequency will be 228.11 rad/sec
Explanation:
We have given Inductance L = 0.048 Henry
And the capacitance C = 0.0004 farad
We have to find natural frequency
When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by 
So the natural frequency will be 228.21
Explanation:
work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)
= 21 ( 11.08 - 132.25)
= 21 ( - 121.17 )
= - 2544.57 J
Answer:
length
<em>Your</em><em> </em><em>well</em><em> </em><em>wisher</em><em> </em><em>:-)</em>
Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:

Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:

G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:

Now, we can solve for the period:
