Answer:
bhj vghvghvjvjvvvvvvvvvvvvv
Step-by-step explanation:
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
B (2, 2)
Step-by-step explanation:
Given the graphs of a system of equations then the solution is at the point of intersection of the 2 lines.
That is (2,2) ← is the solution → B
They are vertical angles, thus they are equal to each other:
5x + 12 = 6x - 10
22 = x
x = 22
