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Elza [17]
3 years ago
6

How to simply this equation

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

\sqrt[3]{2}

Step-by-step explanation:

     18

 9 .     2

3 3

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HELP 5 STAR RATING ADN BRAINLY IF SOLVED!
alexandr402 [8]
It is $84.6. You multiply 1.6 by 13 which equals $20.8. Then you multiply 3.1 by 14 which equals $43.4. Then you multiply 1.2 by 17 which equals $20.4. Add them together and you get $84.6. 

Hope this helps:)<span />
5 0
3 years ago
Read 2 more answers
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
⚠️ Help I don’t understand this one and it’s my last one !! ⚠️
Kruka [31]

Answer:

x=4

Step-by-step explanation:

no because x=4 and you can't have multiple answerd

7 0
3 years ago
Please answer the question and please answer correctly... I really need help
Mekhanik [1.2K]

Answer:

The treatment decays by half each week.

Step-by-step explanation:

The decay function is given by:

y=a(1-r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = decay rate

<em>t </em>= time

The decay function for one medications to treat dogs for fleas is:

F(x)=4\cdot (\frac{1}{2})^{w}

Here the decay rate is:

1-r=\frac{1}{2}\\\\r=1-\frac{1}{2}\\\\r=\frac{1}{2}

The treatment decays by half each week.

3 0
3 years ago
The length of a rectangular piece of land is 60 yard more than two times its width. The perimeter is 540 yard. Find its dimensio
babunello [35]

Answer:

l=200 yard

w=70 yard

Step-by-step explanation:

let  width =w

length l=2w+60

then perimeter P=2(l+w)=2(2w+60+w)=540

3w+60=270

3 w=270-60=210

w=70

l=2*70+60=200

4 0
3 years ago
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