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Lerok [7]
2 years ago
5

The inequality x ≤ −8 represents the possible values for x on a number line. Which is NOT a possible value for x?

Mathematics
2 answers:
sertanlavr [38]2 years ago
8 0

Answer:

Answer is D) -2

Step-by-step explanation:

Answer is D) because those are negative numbers so -2 is closest to zero from other numbers.

lidiya [134]2 years ago
7 0
-2 is the answer bro
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Helppppp what was Fátima’s error?
Gekata [30.6K]

Answer:

She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2.

Step-by-step explanation:

i got my rerecord from my flash cards my teacher made of some answers

3 0
3 years ago
The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o
earnstyle [38]
• First way to solve:
We'll manipulate the expression of the equation:

y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)

If we have y=0:

x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B


• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.
3 0
2 years ago
Need help show work??????
o-na [289]

Answer:

The t-shirt cost $10.70

Step-by-step explanation:

12.25 + T = 22.95

-12.25          -12.25

T=10.70

8 0
2 years ago
The formula A=200e^.033t models the population of a particular city, in thousands, t years after 1998. When will the population
svetoff [14.1K]

Answer:

In the year 2010

Step-by-step explanation:

we have

A=200e^{0.033t}

where

A is the population in thousands

t is the number of years since 1998

so

For A=297 thousands

substitute and solve for t

297=200e^{0.033t}

simplify

1.485=e^{0.033t}

Apply ln both sides

ln(1.485)=ln[e^{0.033t}]

ln(1.485)=(0.033t)ln(e)

Remember that

ln(e)=1

ln(1.485)=(0.033t)

t=\frac{ln(1.485)}{0.033}

t=12\ years

1998+12=2010

7 0
3 years ago
Find the value of the variable not given<br><br> V=1/3Bh;V=18,h=2
Anna [14]
If the first part is V=1/3 of Bh, then B=27
6 0
3 years ago
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