Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.5
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Answer:
2 batches
Step-by-step explanation:
(72 lb)/(34 lb/bat) = 2 2/17 bat
___
72 ÷ 34 = 2 remainder 4.
Mateo can make 2 full batches, and will have 4 pounds of apples remaining.
The fraction 4/34 can be reduced to 2/17. That is the fraction of a batch that Mateo could make with the extra 4 lbs. of apples.
the answer is 13/7 and here is the correct question
the answer is 13/7 and here is the correct questionwhen a customer wants pie for dessert you cut a whole pies into 7 equal slices...at the end of your shift 3/7 of. a cherry pie.2/7. of an apple pie.3/7 of a peach pie.and 5/7 of a blueberry pie remain...How much pie remains as a fraction of. a whole pie...
Answer:
13/7
Step-by-step explanation:
From the question, we have
3/7 of cherry pie
2/7 of apple pie
3/7 of peach pie
5/7 of blueberry pie
Now we have to add up all of these in order to get the total amount of pie
3/7 + 2/7 +3/7 +5/7
= (3+2+3+5)/7
=13/7
If expressed as a mixed fraction
= 1 6/7
In conclusion, 13/7 pie remains as a fraction of a whole.
Im notr sure but if we take the chances that the 4 sum has to be either (1.3) (3.1) (2.2) (2.2) that means its chance is 4/36 for each roll which is also 1/9 ,, we can multiply 1/9 times the roll times ( 252 ) we get =28
-the equation is a quadratic
-the axis of symmetry is x=-7
-the graph has a relative maximum
