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Alik [6]
3 years ago
14

Match the factors which affect the rate of dissolving/dissociation. 1. increased surface area . 2. like polarity increases rate

. 3. temperature 4. stirring . A)rate proportional to K.E.. B)concentration decreases around solute. C)finely divided solute. D)matching solvent and solute
Chemistry
2 answers:
vampirchik [111]3 years ago
6 0

Answer :

            Part A                                                   Part B

1) increased surface area          →      C) finely divided solute

2) like polarity increases rate   →       D)matching solvent and solute

3) temperature                           →       A)rate proportional to K.E

4) stirring                                    →       B)concentration decreases around solute

Explanation :

1) Greater the surface area, the faster the substance will dissolve. When we are finely divided the solute then the surface area increased.

2) A polar molecule will dissolve in other polar molecules, but it will not dissolve in non-polar molecules.

3) Temperature is directly proportional to the kinetic energy. As the temperature increases, the kinetic energy also increases.

4) Stirring a solute into a solvent, the dissolving rate increases and the concentration decreases around the solute.


laiz [17]3 years ago
5 0
The correct matches are as follows:

1. increased surface area
 C)finely divided solute.

2. like polarity increases rate
<span> D)matching solvent and solute
</span>
3. temperature
<span>A)rate proportional to K.E.
</span>
4. <span>stirring
</span>B)concentration decreases around solute.<span>

</span>
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Therefore, the pressure, in bottle A is

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For B:

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Gas constant (R) = 0.0821 atm.L/Kmol

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Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

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Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

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Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

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