So, you could put filters with holes based on the size of the average gram. Which means sugar grams or salt can fit through.
It's an instrument used for measuring ionizing radiation used widely in applications such as radiation dosimetry
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г. магния потребуется 11,2 л. хлора.
Answer:
108.43 g.
Explanation:
- <em>Adding solute (KNO₃) to water causes depression of freezing point of water (collegative properties).</em>
- We can predict the change in the freezing point (ΔTf) of water using the relation:
<em>ΔTf = i.Kf.m,</em>
where, ΔTf is the elevation in boiling water (ΔTf = 0.0°C - (- 14.5°C) = 14.5 °C).
i is van 't Hoff factor, The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.
i for KNO₃ = 2/1 = 2.
Kf is the molal freezing constant of water (Kf = 1.86 °C/m).
m is the molality of the solution.
∵ ΔTf = i.Kf.m,
∴ m = (ΔTf)/(i.Kf) = (14.5°C)/(2)(1.86 °C/m) = 3.9 m.
- <em>molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.</em>
<em>m = (no. of moles of KNO₃)/(mass of water (kg)) = (mass/molar mass of KNO₃)/(mass of water (kg)).</em>
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∴ 3.9 m = (mass of KNO₃ / 101.1 g/mol)/(0.275 kg).
∴ mass of KNO₃ = (3.9 m)(101.1 g/mol)(0.275 kg) = 108.43 g.