What are the solutions to (x+3)(x-4)=0?

Mathematics

1 answer:

marishachu [46]4 years ago

6 0

Answer:

-3, 4

Step-by-step explanation:

(x+3)(x-4)=0

Therefore, x + 3 = 0 and x - 4 = 0

so, x = -3 and x = 4

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$\bf sin(\theta)=\cfrac{y}{r}
\qquad 

% cosine
cos(\theta)=\cfrac{x}{r}\quad 
\begin{cases}
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\end{cases}\\
-----------------------------\\
thus
\\\\

\begin{cases}
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\\\\
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\end{cases}
\\\\
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