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Ainat [17]
4 years ago
9

What are the solutions to (x+3)(x-4)=0?

Mathematics
1 answer:
marishachu [46]4 years ago
6 0

Answer:

-3, 4

Step-by-step explanation:

(x+3)(x-4)=0

Therefore, x + 3 = 0 and x - 4 = 0

so, x = -3 and x = 4

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Four bags of puppies show dog food weight 142 pounds what is the weight in one pound of one bag of the puppy chow dog food
MariettaO [177]

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I think youre trying to ask the weight of one of the bags

Step-by-step explanation:

the answer is 35.5 you take the total weight and divide it by the number of bags hope this helps

4 0
3 years ago
Juan fode his bike 2/3 mile to school,1/3 mile to the library,2/3 mile home far did he ride altogether
Viktor [21]

Answer:1 2/3

Step-by-step explanation:

2/3+1/3+2/3=5/3=1 2/3

7 0
3 years ago
As a decimal number<br> 8×1+1× 1/ 10 +6× 1 /100 +7× 1/ 1000 =
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Step-by-step explanation:

4 0
3 years ago
A shape is shown on the graph: A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to neg
Arada [10]

A shape is shown on the graph: A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 4, negative 2 and 2, negative 6. Which of the following is a reflection of the shape? (5 points) Group of answer choices A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, negative 2 and negative 4, negative 2 and negative 4, negative 6. A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, 2 and 4, 2 and 2, 6. A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, negative 4 and negative 6, negative 4 and negative 6, negative 2. A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, 2 and 2, 4 and 6, 2.

3 0
3 years ago
First-order linear differential equations
kkurt [141]

Answer:

(1)\ logy\ =\ -sint\ +\ c

(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Step-by-step explanation:

1. Given differential equation is

  \dfrac{dy}{dt}+ycost = 0

=>\ \dfrac{dy}{dt}\ =\ -ycost

=>\ \dfrac{dy}{y}\ =\ -cost dt

On integrating both sides, we will have

  \int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}

=>\ logy\ =\ -sint\ +\ c

Hence, the solution of given differential equation can be given by

logy\ =\ -sint\ +\ c.

2. Given differential equation,

    \dfrac{dy}{dt}\ -\ 2ty\ =\ t

=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty

=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})

=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt

On integrating both sides, we will have

   \int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}

=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c

=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Hence, the solution of given differential equation is

log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

8 0
4 years ago
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