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3 years ago

What is the exponential regression equation to best fit the data?

1 answer:

4 0

What is the exponential regression equation to best fit the data?

Round each value in your equation to two decimal places.

Enter your answer in the box.

yˆ =

$\text{Basic}$
$x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$
$x\frac{ }{ }$
$x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$
x y
0 14
1 23
2 30
3 58
4 137
5 310

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If x = 3 and Y = 5 work out the value of 2x squared + 3 Y squared

miskamm [114]

Answer:

Step-by-step explanation:

x = 3

y = 5

2x^2 + 3y^2 = 2 × 3^2 + 3 × 5^2

= 2 × 9 + 3 × 25

= 18 + 75

= 93

Hope this helps

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3 years ago

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18, 7 The LCM of 18 and 7 is

Korvikt [17]

Answer:

126

Step-by-step explanation:

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3 years ago

Choose the graph below that represents the following system of inequalities:

castortr0y [4]

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2 years ago

GEOMETRY. 20 POINTS. PLEASE DO NOT GIVE STUPID ANSWERS.

sp2606 [1]

Hey there!

A quadrilateral has 360 degrees. So add all the degrees together to 360. 9x+1+5x-12+8x+61+90=360. 90 degrees is in the bottom left corner. Combine like terms. 22x+140=360. Subtract 140 from each side. 22x=220. Divide 22 on each side to get x=10. Plug in 10 for x in angle D. 5(10)-12=38. The measure of angle D is 38 degrees.

I hope this helps!

3 0

3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago