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bogdanovich [222]

2 years ago

7

What is the exponential regression equation to best fit the data?

1 answer:

ollegr [7]2 years ago

4 0

What is the exponential regression equation to best fit the data?

Round each value in your equation to two decimal places.

Enter your answer in the box.

yˆ =

$\text{Basic}$
$x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$
$x\frac{ }{ }$
$x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$
x y
0 14
1 23
2 30
3 58
4 137
5 310

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What is 3/16 as decimal

LenaWriter [7]

Put 3 divided by 16 into your calculator

8 0

2 years ago

The penguins currently living on an island are of two types, Chinstrap penguins and Gentoo penguins. The range of the heights of

velikii [3]

Answer:

The answer is "Option A"

Step-by-step explanation:

Using the range difference to calculate the maximum and minimum value.

The range of the chinstrap penguins are:

$R(c) = Max(c) - Min(c) = 13.2$

The range of the Gentoo penguins are:

$R(g) = Max(g) - Min(g) = 15.4$

For point A:

$Max(c) = x\\\\Max(g) = x + 5.8\\\\R(c) = x - Min(c) = 13.2 \to x = 13.2 + Min(c)\\\\R(g) = x + 5.8 - Min(g) = 15.4 \to x = 9.6 + Min(g)$

equate both of them

$13.2 + Min(c) = 9.6 + Min(g)Min(g) - Min(c) = 3.6$

It indicates that Min(c) surpasses Min(g), whereas Max(g) exceeds Max (c).

Therefore, the Max is picked for g for all penguins and the minimum is picked for c.

Range of all penguins $= Max(g) - Min(c) = x + 5.8 - x + 13.2 = 19$

Therefore, it will be determined as the option.

For point B:

In estimating the range the median height cannot help.

For point C:

In order to calculate the variety, the connection between both the mean height cannot be sued.

7 0

2 years ago

What is the standard form of 3^5

sineoko [7]

Answer:

3*3*3*3*3

Step-by-step explanation:

6 0

2 years ago

Find a point slope form for the line with slope 1/5 and passing through the point (-3,-9)

alisha [4.7K]

Answer:

y+9=1/5(x+3)

Step-by-step explanation:

Point slope formula: y-y1=m(x-x1)

slope=m

m=1/5

-3=x1 -9=y1

y-(-9) =1/5(x-(-3))

simplify...

y+9=1/5(x+3)

hope this helps!! :)

5 0

2 years ago

A sample of 16 items from population 1 has a sample variance 5.8 and a sample of 21 items from population 2 has a sample varianc

Nady [450]

Answer:

Reject the null hypothesis.

Step-by-step explanation:

n1 = 16

n2 = 21

S.V1 = 5.8

S.V2 = 2.4

$\alpha$ = 0.05

$H_{0}$ = Population Variance 1 ≤ Population Variance 2

$H_{a}$ = Population Variance 1 > Population Variance 2

Test statistic value = 5.8 / 2.4 = 2.417

Degrees of freedom is n - 1

15 and 20

Critical value is $F_{0.05}$ = 2.2

2.417 > 2.2

we reject the null hypothesis as the critical value is greater than the test statistic.

3 0

2 years ago