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uranmaximum [27]
4 years ago
8

The perimeter of a pentagon is 20t+7. Four sides have the following lengths: 6t, 2t, 4t-5, and 5t+1.What is the length of the fi

fth side?
Mathematics
1 answer:
julia-pushkina [17]4 years ago
3 0
3t+11 bc add all the other sides then subtract from total
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Degree 3 polynomial with zeros 4, 6, and -2.
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Step-by-step explanation:

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an Degree 3 polynomial with zeros 4, 6, and -2 is :

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3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

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width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

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And ,

y = 21-x\\y = 21-11\\y = 10 inches

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7 0
3 years ago
A pole that is 3 m tall casts a shadow that is 1.74 m long at the same time a nearby building casts a shadow that is 50.75 m lon
bija089 [108]
87.5

Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5
4 0
3 years ago
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