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White raven [17]
4 years ago
6

When you drain the solution from the bottom, the concentration will:

Chemistry
1 answer:
djverab [1.8K]4 years ago
3 0

.Answer:

stay the same the conc. of a solution is the same throughout the liquid

Explanation:

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1. Define each of the ways that matter is measured:<br> a. Mass-<br><br> b. Volume -
adoni [48]

Answer:

Explanation:

Mass is how much an object weighs . Volume is the amount of space the object takes up

4 0
3 years ago
Acetonitrile, CH3CN, is a polar organic solvent that dissolves many solutes, including many salts. The density of a 1.80 M aceto
GarryVolchara [31]

Answer:

(a) m=2.69m

(b) x_{LiBr}=0.099

(c) \% LiBr=18.9\%

Explanation:

Hello,

In this case, given the molality in mol/L, we can compute the required units of concentration assuming a 1-L solution of acetonitrile and lithium bromide that has 1.80 moles of lithium bromide:

(a) For the molality, we first compute the grams of lithium bromide in 1.80 moles by using its molar mass:

m_{LiBr}=1.80mol*\frac{86.845 g}{1mol}=156.32g

Next, we compute the mass of the solution:

m_{solution}=1L*0.826\frac{g}{mL}*\frac{1000mL}{1L}=826g

Then, the mass of the solvent (acetonitrile) in kg:

m_{solvent}=(826g-156.32g)*\frac{1kg}{1000g}=0.670kg

Finally, the molality:

m=\frac{1.80mol}{0.670kg} \\\\m=2.69m

(b) For the mole fraction, we first compute the moles of solvent (acetonitrile):

n_{solvent}=669.68g*\frac{1mol}{41.05 g} =16.31mol

Then, the mole fraction of lithium bromide:

x_{LiBr}=\frac{1.80mol}{1.80mol+16.31mol}\\ \\x_{LiBr}=0.099

(c) Finally, the mass percentage with the previously computed masses:

\% LiBr=\frac{156.32g}{826g}*100\%\\ \\\% LiBr=18.9\%

Regards.

4 0
4 years ago
Can someone help me with this?
gavmur [86]
With what? fhdvsbjnkmla,ksxbcvb nmajndvhbfjn m



5 0
4 years ago
When water boils in a pan on a hot burner, heat gets to the water mainly by. A. absorption of heat from the air in the room. B.
xxTIMURxx [149]
B. The heat travels to the pan and therefore heats the water
5 0
3 years ago
Read 2 more answers
Cobalt-60, with a half-life of 5.0 days, is used in cancer radiation treatments. A hospital purchases a 30.0g supply of it and s
Rudik [331]

Answer:

Bottle is sitting on the shelf for 15 days.

Explanation:

Given data:

Co-60 half life = 5 days

Total amount = 30.0 g

Amount left = 3.75 g

Time taken = ?

Solution:

AT time zero = 30 g

AT first half life= 30g /2 = 15 g

At 2nd half life = 15 g/ 2 = 7.5 g

At 3rd half life = 7.5 g/2 = 3.75 g

Now we will calculate the sitting time of bottle.

Half life = Time taken / number of half lives

3× 5 days = time taken

Time taken = 15 days

Bottle is sitting on the shelf for 15 days.

8 0
3 years ago
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