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jolli1 [7]
3 years ago
11

What is the most likely source of the carbon dioxide shown in the graph above?

Chemistry
1 answer:
castortr0y [4]3 years ago
7 0

Combustion of fossil fuels

Explanation:

The most likely source of the carbon dioxide shown in the graph is the combustion of fossil fuels for both industrial and domestic use.

  • Fossil fuels are hydrocarbon units.
  • They burn in the presence of oxygen gas to from carbon dioxide and water.
  • The level of carbon dioxide has been increasing dramatically with increase in industrialization.
  • The fuels are used and needed for the workings of machinery.
  • Domestically they are used in heating homes and powering automobiles.
  • These processes produce carbon dioxide as a waste product.

learn more:

Green house gas emission brainly.com/question/4580761

#learnwithBrainly

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A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO3 in a coffee cup calorimeter. If both solutions
Mandarinka [93]

Answer:

\boxed{\text{-55.8 kJ/mol NaOH}}

Explanation:

NaOH + HNO₃ ⟶ NaNO₃ + H₂O

There are two energy flows in this reaction.

\begin{array}{cccl}\text{Heat from neutralization} & + &\text{Heat absorbed by water} & = 0\\q_{1} & + & q_{2} & =0\\n\DeltaH & + & mC\Delta T & =0\\\end{array}

Data:

V(base) = 100.0 mL; c(base) = 0.300 mol·L⁻¹

V(acid) = 100.0 mL; c (acid) = 0.300 mol·L⁻¹  

        T₁ = 35.00 °C;          T₂ = 37.00 °C

Calculations:

(a) q₁

n_{\text{NaOH}} = \text{0.1000 L } \times \dfrac{\text{0.300 mol}}{\text{1 L}} = \text{0.0300 mol}\\\\n_{\text{HNO}_{3}} = \text{0.1000 L } \times \dfrac{\text{0.300 mol}}{\text{1 L}} = \text{0.0300 mol}

We have equimolar amounts of NaOH and HNO₃

n = 0.0300 mol

q₁ = 0.0300ΔH

(b) q₂

 V = 100.0 mL + 100.0 mL = 200.0 mL

m = 200.0 g

ΔT = T₂ - T₁ = 37.00 °C – 35.00 °C = 2.00 °C

q₂ = 200.0 × 4.184 × 2.00 = 1674 J

(c) ΔH

0.0300ΔH + 1674 = 0

          0.0300ΔH = -1674

                      ΔH = -1674/0.0300

                      ΔH = -55 800 J/mol

                      ΔH = -55.8 kJ/mol

\Delta_{r}H^{\circ} = \boxed{\textbf{-55.8 kJ/mol NaOH}}

6 0
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I hope this helps...

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-Dominant- [34]

Some people reacted so strongly because it went against their cultures and religious beliefs

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Why does the malachite green dye elute first? What physical properties does it have that affect it’s interaction with alumina an
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Answer:

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