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ratelena [41]
3 years ago
5

Please Help , Thank You

Chemistry
1 answer:
ivanzaharov [21]3 years ago
8 0
I think it enters a new  material
You might be interested in
What is the noble gas configuration for zirconium?
Mkey [24]

Answer:

[Kr] 4d² 5s²

Explanation:

5 0
3 years ago
What are some of the reasons for arguing against adjusting what metals coins are made out of? (use textual evidence)
Luba_88 [7]

Answer:

copper

Explanation:

5 0
3 years ago
Identify the oxidized and reduced forms from the following pairs:
Luden [163]

Answer:

1. NAD⁺ is the oxidized form and NADH  is the reduced form

2. Pyruvate is the oxidized form and Lactate is the reduced form.

3. Oxaloacetate is the oxidized form and Malate is the reduced form.

4. Fumarate is the oxidized form and Succinate is the reduced form.

5. FMN is the oxidized form and FMNH₂  is the reduced form

6. α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.

7. O₂ is the oxidized form and  H₂O₂ is the reduced form.

Explanation:

Oxidation is the gain of oxygen or loss of electrons or hydrogen. Whereas, reduction is the loss of oxygen or gain of electrons or hydrogen.

1. NAD⁺/NADH

<u>NAD⁺ is the oxidized form and NADH  is the reduced form of Nicotinamide adenine dinucleotide, NAD.</u>

Therefore, NAD⁺ gets reduced to NADH by accepting electrons and proton.

NAD⁺ + 2 e⁻ + H⁺ → NADH

2. Pyruvate/lactate

Pyruvate, CH₃COCOO⁻, is the conjugate base of Pyruvic acid.

Lactate, CH ₃CH(OH)COO⁻, is the conjugate base of Lactic acid.

Reduction of Pyruvate to lactate:

CH₃COCOO⁻ + NADH  ⇌ CH ₃CH(OH)COO⁻ + NAD⁺

This reaction is catalyzed by the enzyme lactate dehydrogenase.

<u>Therefore, Pyruvate is the oxidized form and Lactate is the reduced form.</u>

3. Malate/oxaloacetate

Oxaloacetate, ⁻O₂CC(O)CH₂CO₂⁻, is the conjugate base of oxaloacetic acid.

Malate,⁻O₂CCH(OH)CH₂CO₂⁻, is the conjugate base of Malic acid.

Oxidation of Malate to Oxaloacetate:

⁻O₂CCH(OH)CH₂CO₂⁻ + NAD⁺  ⇌ ⁻O₂CC(O)CH₂CO₂⁻ + NADH

This reaction is catalyzed by the enzyme malate dehydrogenase.

<u>Therefore, Oxaloacetate is the oxidized form and Malate is the reduced form.</u>

4. Fumarate/succinate

Fumarate, ⁻O₂CCH=CHCO₂⁻, is the conjugate base of Fumaric acid.

Succinate, ⁻O₂CCH₂CH₂CO₂⁻, is the conjugate base of Succinic acid.

Oxidation of succinate to fumarate:

⁻O₂CCH₂CH₂CO₂⁻ + FAD ⇌ ⁻O₂CCH=CHCO₂⁻ + FADH₂

This reaction is catalyzed by the enzyme succinate dehydrogenase.

<u>Therefore, fumarate is the oxidized form and succinate is the reduced form.</u>

<u />

5. FMN/FMNH₂

<u>FMN is the oxidized form and FMNH₂  is the reduced form</u> of riboflavin-5′-phosphate or Flavin mononucleotide.

Therefore, FMN gets reduced to FMNH₂  by accepting electrons and proton.

FMN + 2 e⁻ + 2H⁺ → FMNH₂

     

6. α-ketoglutarate/isocitrate

α-ketoglutarate, ⁻O₂CC(O)CH₂CH₂CO₂⁻, is the conjugate base of α-Ketoglutaric acid.

Isocitrate, ⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻, is the conjugate base Isocitric acid.

Oxidation of Isocitrate to α-ketoglutarate:

⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻ + NAD⁺ → ⁻O₂CC(O)CH₂CH₂CO₂⁻ + CO₂ + NADH

This reaction is catalyzed by the enzyme Isocitrate dehydrogenase.

<u>Therefore, α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.</u>

<u />

7. H₂O₂/O₂

Hydrogen peroxide, H₂O₂, is synthesized from hydrogen (H₂) and oxygen (O₂) in the presence of a catalyst.

H₂ + O₂ → H₂O₂

Oxygen gets reduced from 0 oxidation state in O₂ to -1 oxidation state in H₂O₂.

<u>Therefore, O₂ is the oxidized form and  H₂O₂ is the reduced form.</u>

8 0
3 years ago
Fe(s)+CuSO4(aq)========Cu(s)+FeSO4(aq)*Note both 4's are subscripts and the equal signs represent an arrow.Suppose an industrial
igomit [66]

<u>Answer:</u> The original concentration of copper sulfate is 0.56 g/L

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of copper = 89 mg = 0.089 g   (Conversion factor: 1 g = 1000 mg)

Molar mass of copper = 63.5 g/mol

Putting values in equation 1, we get:

\text{Moles of copper}=\frac{0.089g}{63.5g/mol}=0.0014mol

The given chemical equation follows:

Fe(s)+CuSO_4(aq.)\rightarrow Cu(s)+FeSO_4(aq.)

By Stoichiometry of the reaction:

1 mole of copper metal is produced by 1 mole of copper sulfate

So, 0.0014 moles of copper metal will be produced by = \frac{1}{1}\times 0.0014=0.0014mol of copper sulfate

Now, calculating the mass of copper sulfate from equation 1, we get:

Molar mass of copper sulfate = 159.6 g/mol

Moles of copper sulfate = 0.0014 moles

Putting values in equation 1, we get:

0.0014mol=\frac{\text{Mass of copper sulfate}}{159.6g/mol}\\\\\text{Mass of copper sulfate}=(0.0014mol\times 159.6g/mol)=0.223g

  • Calculating the original concentration of copper sulfate:

Mass of copper sulfate = 0.223 g

Volume of copper sulfate = 400 mL = 0.400 L    (Conversion factor: 1 L = 1000 mL)

\text{Original concentration of copper sulfate}=\frac{0.223g}{0.400L}=0.56g/L

Hence, the original concentration of copper sulfate is 0.56 g/L

7 0
3 years ago
The nonvolatile, nonelectrolyte urea, CH4N2O (60.1 g/mol), is soluble in water, H2O. How many grams of urea are needed to genera
Sergeeva-Olga [200]

<u>Answer:</u> The mass of urea needed is 12.89 grams

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT

where,

\pi = osmotic pressure of the solution = 24.3 atm

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of urea = ? g

M_{solute} = molar mass of urea = 60.1 g/mol

V_{solution} = Volume of solution = 216 mL

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

24.3atm=1\times \frac{m_{solute}\times 1000}{60.1\times 216}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\m_{solute}=\frac{24.3\times 60.1\times 216}{1\times 1000\times 0.0821\times 298}=12.89g

Hence, the mass of urea needed is 12.89 grams

3 0
3 years ago
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