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bulgar [2K]
3 years ago
5

Cobalt-60, with a half-life of 5.0 days, is used in cancer radiation treatments. A hospital purchases a 30.0g supply of it and s

tores it on a shelf in a closet. The next time a hospital worker grabs the bottle, though, they find that it only contains 3.75 g remaining! Assuming the bottle had never been opened, how long was the bottle sitting on the shelf before the worked grabbed it?
Chemistry
1 answer:
Rudik [331]3 years ago
8 0

Answer:

Bottle is sitting on the shelf for 15 days.

Explanation:

Given data:

Co-60 half life = 5 days

Total amount = 30.0 g

Amount left = 3.75 g

Time taken = ?

Solution:

AT time zero = 30 g

AT first half life= 30g /2 = 15 g

At 2nd half life = 15 g/ 2 = 7.5 g

At 3rd half life = 7.5 g/2 = 3.75 g

Now we will calculate the sitting time of bottle.

Half life = Time taken / number of half lives

3× 5 days = time taken

Time taken = 15 days

Bottle is sitting on the shelf for 15 days.

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A covalent bond is best described as ______(A) a bond between two polyatomic ions.(B) a bond between a metal and a nonmetal.(C)
nekit [7.7K]

Answer:

Option C. the sharing of electrons between atoms

Explanation:

Covalent bond is a type of bond in which the reacting element share their valence electrons in order to attain the noble gas configuration.

4 0
3 years ago
An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?
julsineya [31]

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

Learn more about density:

brainly.com/question/952755

3 0
2 years ago
How much energy (heat) is required to convert 52.0 g of ice at –10.0°C to steam at 100°C? Specific heat of ice 2.09 J/g • °C Spe
dexar [7]

Answer: The energy (heat) required to convert 52.0 g of ice at –10.0°C to steam at 100°C is 157.8 kJ

Explanation:

Using this formular, q = [mCpΔT] and = [nΔHfusion]

The energy that is needed in the different physical changes is thus:

The heat needed to raise the ice temperature from -10.0°C to 0°C is given as as:

q = [mCpΔT]

q = 52.0 x 2.09 x 10

q = 1.09 kJ

While from 0°C to 100°C is calculated as:

q = [mCpΔT]

q = 52.0 x 4.18 x 100

q = 21.74 kJ

And for fusion at 0°C is called Heat of fusion and would be given as:

q = n ΔHfusion

q = 52.0 / 18.02 x 6.02

q = 17.38 kJ

And that required for vaporization at 100°C is called Heat of vaporization and it's given as:

q = n ΔHvaporization

q = 52.0 / 18.02 x 40.7

q = 117.45 kJ

Add up all the energy gives 157.8 kJ

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3 years ago
Which of the following best describes chicken noodle soup?
SSSSS [86.1K]
Chicken noodle soup would be considered a mixture.
3 0
3 years ago
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24. H2SO4 has
Eddi Din [679]

Answer:

C.

Explanation:

para sakin letter C ganonn

3 0
3 years ago
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