2 years ago

Need help pls I don’t really remember functions if anyone could pls help that would be great pls and thank you.

1 answer:

4 0

The third one is not a function

because there is two different outputs (y values) for on input (x value). The X value 4, can’t have and input of 1 and 2

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The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de

ad-work [718]

If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
$z=\frac{173-154}{29}=0.655$
Referring to a standard normal distribution table, and using z = 0.66, we find:
$P(\bar x\ \textless \ 173)=0.7454$
Therefore
$P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546$
The answer is: 0.2546

4 0

4 years ago

Please help with this

Ghella [55]

5/1 because I know it

7 0

3 years ago

Ben says that n=5 is the solution of the equation 7n=45. How can you check whether Ben is correct?

GalinKa [24]

Answer:

Its not. 45 would have to be 35 for n to be 5.

Step-by-step explanation: