If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:

Referring to a standard normal distribution table, and using z = 0.66, we find:

Therefore

The answer is: 0.2546
Answer:
Its not. 45 would have to be 35 for n to be 5.
Step-by-step explanation:
7(5)=45
|y-9|=6
y-9=6
y-9=-6
y=15
y=3
So, y=15,3