9x^2 - 16x + 60 Find the discriminant, b^2 - 4ac, which is the same as the value of the radicand. (-16)^2 - 4 * 9 * 60 = -1904 Since the discriminant is negative, there will be NO real solutions, and 2 complex solutions.
Part B. 4x^2 + 8x - 5 = 0 You can tell if a quadratic is factorable if you find the discriminant and it is a perfect square. The discriminant for this quadratic is 144 so it is factorable. (2x + 5)(2x - 1) = 0 Set each factor equal to zero. 2x + 5 = 0 2x - 1 = 0 subt 5 from both sides add 1 to both sides 2x = -5 2x = 1 divide both sides by 2 divide both sides by 2 x = -5/2 <span> </span> x = 1/2
