Answer:
5.6L
Explanation:
Given parameters:
number of moles = 0.25mol
pressure on gas = 1atm
temperature = 273K
Gas constant R = 0.0821Latm/molK
Unknown:
Volume of gas = ?
Solution:
Using the ideal gas equation, we can solve this problem. The equation is a combination of the three gas laws: Boyle's law, Charles's law and Avogadro's law.
It is mathematically expressed as;
PV = nRT
where P is the pressure
V is the volume
R is the gas constant
T is the temperature
n is the number of moles
All the parameters are in the appropriate units and we simply solve for the volume of the gas;
1 x V = 0.25 x 0.0821 x 273
V = 5.6L
Elephants are herbivores because their diet consists mainly of plants and leafy greens. Herbivores only eat plants therefore elephants are herbivores.
Cumulative frequency is the right answer
Answer:
ΔG'° for the coupled reaction = -16.7 kJ/mol
<em>Note: The question is missing some parts. The complete question is as follows:</em>
<em>The first reaction in glycolysis is the phosphorylation of glucose:
</em>
<em>
Pi+glucose⟶glucose−6−phosphate+H2O
</em>
<em>This is a thermodynamically unfavorable process, with ΔG∘′= +13.8kJ/mol. In a liver cell at 37 ∘C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each.</em>
<em>This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H+</em>
<em>What is the ΔG'° for the coupled reaction?</em>
Explanation:
The coupling of ATP hydrolysis which is a thermodynamically favourable reaction to the phosphorylation of glucose makes it favourable. Since the two reactions constitute a sequential reaction, their standard free energy changes are additive.
For ATP hydrolysis: ATP + H₂O ---> ADP + Pi ; ΔG'° = -30.5KJ/mol
For phosphorylation of glucose: Pi + glucose⟶glucose−6−phosphate + H2O ; ΔG'° = +13.8 kJ/Mol
For the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H⁺ ; ΔG'° = 13.8 + (-30.5) kJ/mol = -16.7 kJ/mol
Therefore, ΔG'° for the coupled reaction = -16.7 kJ/mol