Step-by-step explanation:
Using Pythagoras theoram,
AC²= AB²+BC²
Answer:
The growth rate he needs to achieve his goal is approximatelly 19.8%
Step-by-step explanation:
Since the sum will be compounded continuously we have to use the appropriate formula given below:
M = C*e^(r*t)
Where "M" is the final amount, C is the initial amount, r is the interest rate and t is the time elapsed. Since Sung Lee will invest that sum at 18 years old and he wants to recieve the return at 25, then the time elapsed is given by 25 -18 = 7 years. We can now apply the data to the formula:
16000 = 4000*e^(r*7)
4000*e^(7*r) = 16000
e^(7*r) = 16000/4000 = 4
ln[e^(7*r)] = ln(4)
7*r = ln(4)
r = ln(4)/7 = 0.198
The rate of interest is given by (r)*100%, so we have (0.198)*100% = 19.8%.
Answer:
c
Step-by-step explanation:
First, from A to B, x=6, but y ranges from 8 to -8. From B to C, y=-8, but x ranges from 6 to -6. From C to D, x=-6, but y ranges from -8 to 8. From D to A, y=8, but x ranges from -6 to 6.
The ranges are as follows:
- x goes from -6 to 6
- y goes from -8 to 8
There are no x values less than -6, no x values greater than 6, no y values less than -8, and no y values greater than 8. x is always greater than or equal to -6 and less than or equal to 6. y is always greater than or equal to -8 and less than or equal to 8. We can write these as inequalities as follows:
x ≥ -6
x ≤ 6
y ≥ -8
y ≤ 8
The answer that is not in these 4 is c. y ≤ -8. y is never less than -8, so this is wrong
Hello there!
1/3 (9 - 6x) = x
Start by using the distributive form
(1/3)(9) + (1/3)(-6x) = x
9/3 + (-6x)/3 = x
3 - 2x = x
-2x + 3 = x
-2x - x + 3 = 0
-3x + 3 = 0
-3x = 0 - 3
-3x = -3
x = -3/-3
x= 1
It is always my pleasure to help people like you. As always, I am here to help!
The answer is x>-2 first you just move the -1 by adding 1 to both sides. Then you get 4x>-8 then you must isolate the x by dividing the 4 on both sides. After you divide it you will have just x on one side of the inequality and -2 on the other side. this will leave you with the inequality x>-2
