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vova2212 [387]
3 years ago
6

What is the role of the water cycle in maintaining freshwater levels in lake and rivers?

Physics
1 answer:
Anika [276]3 years ago
6 0

Replenishes Freshwater resources  and moderates extremes in climate :))

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Describe what happens to radiant energy once it enters the atmosphere? How does Radiant energy cause weather?
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Once energy from the Sun gets to Earth, several things can happen to it:

Energy can be scattered or absorbed by aerosols in the atmosphere. Aerosols are dust, soot, sulfates and nitric oxides. When aerosols absorb energy, the atmosphere becomes warmer. When aerosols scatter energy, the atmosphere is cooled.
Short wavelengths are absorbed by ozone in the stratosphere.
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3 years ago
"If there were no atmosphere, the tiny molecules of gases and dust particles in the air break up and scatter the light of the su
ELEN [110]

if there was no atmosphere,the tiny molecules of gases and dust particles will gather together and rain down while the sun shine on the particles making the color glow because the colors are combining into various of colors looking like the galaxy.

5 0
3 years ago
you need to measure the length of your driveway. which measuring tool would you produce accurate results that you would expectto
lesantik [10]
I’d assume a tape measure?
3 0
4 years ago
Read 2 more answers
A typical jetliner lands at a speed of 146 mi/h and decelerates at the rate of (10.4 mi/h)/s. If the jetliner travels at a const
zzz [600]

jetliner is moving with speed 146 mi/h

now we will have

v= 146 \frac{1609 m}{3600 s}

v = 65.25 m/s

now if it moves with this speed for 1.5 s

so the displacement for above time

d_1 = 1.5(65.25) = 97.9 m

now the deceleration of jet is given as

a = - 10.4 mi/h/s

a = -(10.4)(\frac{1609 m}{3600 s})\frac{1}{s}

a = - 4.65 m/s^2

now by kinematics

v_f^2 - v_i^2 = 2ad

0 - 65.25^2 = 2(-4.65)(d_2)

d_2 = 457.8 m

so total displacement is given as

d = d_1 + d_2

d = 97.9 + 457.8 = 555.7 m

so displacement will be 555.7 m

7 0
3 years ago
Read 2 more answers
A 1kg sphere rotates in a circular path of radius 0.2m from rest and it reaches an angular speed of 20rad/sec in 10 second calcu
Len [333]

Answer:

0.4 m/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1 kg

Radius (r) = 0.2 m

Angular speed (w) = 20 rad/sec

Time (t) = 10 s

Tangential acceleration (aₜ) =?

Next, we shall determine the angular acceleration (a) of the sphere. This can be obtained as follow:

Angular speed (w) = 20 rad/sec

Time (t) = 10 s

Angular acceleration (a) =?

a = w/t

a = 20/10

a = 2 rad/s²

Finally, we shall determine the tangential acceleration (aₜ) of the sphere. This can be obtained as follow:

The tangential acceleration (aₜ) and the angular acceleration (a) are related according to the equation:

Tangential acceleration (aₜ) = Angular acceleration (a) × Radius (r)

aₜ = ar

With the above formula, we can obtain the tangential acceleration (aₜ) as follow:

Radius (r) = 0.2 m

Angular acceleration (a) = 2 rad/s²

Tangential acceleration (aₜ) =?

aₜ = ar

aₜ = 2 × 0.2

aₜ = 0.4 m/s²

Therefore, the tangential acceleration is 0.4 m/s²

6 0
3 years ago
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