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I am Lyosha [343]
3 years ago
9

When asked how to create an electromagnet, the best answer would be, "You can create an electromagnet by

Physics
2 answers:
irinina [24]3 years ago
5 0

The correct answer is D. wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.

Explanation

An electromagnet is a non permanent magnet that is created with an electric current .When current flows through a wire it induces  a magnetic field around the wire. When the wire is wrapped around in a coil, the magnetic field that is induced is concentrated in the center of the coil, creating a north and south pole.   The field is that of a solenoid.  

Electromagnets are usually made by wrapping insulated coil of wire around a ferromagnetic metal. This focuses the electromagnetic field and creates a magnet as long as there is current running trough the insulated wire.

The correct answer is D. wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.

Norma-Jean [14]3 years ago
4 0
Choice-D will do the job nicely.
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Why environmental science is about social action​
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3 years ago
On a cold winter day when the temperature is −20∘C, what amount of heat is needed to warm to body temperature (37 ∘C) the 0.50 L
vlabodo [156]

Answer:

75.6J

Explanation:

Hi!

To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,

Given the above we have the following equation.

Q=(m)(h2)-(m)(h1)

where

m=mass=1.3×10−3kg.

h2= entalpy at 37C

h1= entalpy at -20C

Q=m(h2-h1)

remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference

Q=mCp(T2-T1)

Cp= specific heat of air = 1020 J/kg⋅K

Q=(1.3×10−3)(1020)(37-(-20))=75.6J

4 0
3 years ago
In a ____ wave, pasticles of the medium move perpendicular<br> to the direction of the wave.
GrogVix [38]
The answer is transverse
6 0
3 years ago
A wheel is rotating freely at angular speed 420 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi
Mashcka [7]

Answer:60 rev/min

Explanation:

Given

angular speed of first shaft \omega _1=420\ rev/min

Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment  of inertia of first wheel so moment of inertia of second is 7 I

As there is no external torque therefore angular momentum is conserved

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I_1\omega _1=I_2\omega _2

I\times (420)=7 I\times (\omega _2)

\omega _2=\frac{420}{7}

\omega _2=60\ rev/min  

8 0
4 years ago
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