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grigory [225]
4 years ago
14

you need to measure the length of your driveway. which measuring tool would you produce accurate results that you would expectto

be the same as those found by others
Physics
2 answers:
lesantik [10]4 years ago
3 0
I’d assume a tape measure?
mihalych1998 [28]4 years ago
3 0

Answer: A meter tape will be a good fit for the job

Explanation: What is a driveway? It is a type of private road for local access to one or a small group of structures, and is owned and maintained by an individual or group. Hence what will do the job in my opinion is a meter tape

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Which type of bone is this <br>covalent bond<br>hydrogen bond <br>ionic bond​
Fynjy0 [20]

Answer:

Explanation:A covalent bond is formed when electrons are shared between non-metal atoms, and the positive nuclei are attracted towards the pair of negative bonded electrons. ... Hence, the hydrogen bond is weaker than ionic and covalent bonds. Example: Water molecules are held to each other by intermolecular forces of attraction.

5 0
4 years ago
Consider a model of a hydrogen atom in which an electron is in a circular orbit of radius r = 5.92×10−11 m around a stationary p
DaniilM [7]

Answer:

2.068 x 10^6 m / s

Explanation:

radius, r = 5.92 x 10^-11 m

mass of electron, m = 9.1 x 10^-31 kg

charge of electron, q = 1.6 x 10^-19 C

As the electron is revolving in a circular path, it experiences a centripetal force which is balanced by the electrostatic force between the electron and the nucleus.

centripetal force = \frac{mv^{2}}{r}

Electrostatic force = \frac{kq^{2}}{r^{2}}

where, k be the Coulombic constant, k = 9 x 10^9 Nm^2 / C^2

So, balancing both the forces we get

\frac{kq^{2}}{r^{2}}=\frac{mv^{2}}{r}

v=\sqrt{\frac{kq^{2}}{mr}}

v=\sqrt{\frac{9\times 10^{9}\times1.6\times 10^{-19}\times 1.6\times 10^{-19}}{9.1\times 10^{-31}\times 5.92\times10^{-11}}}

v = 2.068 x 10^6 m / s

Thus, the speed of the electron is give by  2.068 x 10^6 m / s.

6 0
3 years ago
What is meant by 'wasted energy'?
schepotkina [342]
Wasted energy is an energy which is transformed without significant use.
5 0
3 years ago
Read 2 more answers
Your teacher (175kg) and the lab (15kg) are 2m apart. What is the gravitational force between them? Draw a FBD, and label
Pachacha [2.7K]
The gravitational force between two objects is given by
F=G \frac{m_1 m_2 }{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

In this problem, m_1 = 175 kg, m_2 =15 kg and r=2 m, therefore the gravitational force between the two objects is
F=(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}) \frac{(175 kg)(15 kg)}{(2m)^2}=4.38 \cdot10^{-8} N
7 0
3 years ago
Does mars has a bulge near its equator ?
Keith_Richards [23]
Yessir it sure does
7 0
3 years ago
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