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Alex17521 [72]
3 years ago
13

Julia went to 10 houses on her street for Halloween. 5 of the houses gave her a chocolate bar. What fraction of houses on Julia’

s street gave her a chocolate bar?​
Mathematics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

5/10 houses gave ger chocolate so to spimplify you divide the 5 by 5 and u get one and then divide the 10 by 5 which gives u 2

so 1/2

Mnenie [13.5K]3 years ago
3 0

Answer:

1/2

Step-by-step explanation:

5/10 houses gave her chocolate

if you simplify 5/10 by dividing by both the top and bottom by 5 to get 1/2

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The sum of two consecutive integers is -37 find the integers
dexar [7]
The answer could possibly be -48+11=-37
6 0
3 years ago
Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?
Sonbull [250]

Answer:

-6 < k < 2

Step-by-step explanation:

Given

y = x^2 - 2x

y =kx -4

Required

Possible values of k

The general quadratic equation is:

ax^2 + bx + c = 0

Subtract y = x^2 - 2x and y =kx -4

y - y = x^2 - 2x - kx +4

0 = x^2 - 2x - kx +4

Factorize:

0 = x^2 +x(-2 - k) +4

Rewrite as:

x^2 +x(-2 - k) +4=0

Compare the above equation to: ax^2 + bx + c = 0

a = 1

b= -2-k

c =4

For the equation to have two distinct solution, the following must be true:

b^2 - 4ac > 0

So, we have:

(-2-k)^2 -4*1*4>0

(-2-k)^2 -16>0

Expand

4 +4k+k^2-16>0

Rewrite as:

k^2 + 4k - 16 + 4 >0

k^2 + 4k - 12 >0

Expand

k^2 + 6k-2k - 12 >0

Factorize

k(k + 6)-2(k + 6) >0

Factor out k + 6

(k -2)(k + 6) >0

Split:

k -2 > 0 or k + 6> 0

So:

k > 2 or k > -6

To make the above inequality true, we set:

k < 2 or k >-6

So, the set of values of k is:

-6 < k < 2

3 0
3 years ago
Can somebody solve this for me please?
Karo-lina-s [1.5K]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
Express 2/2 as a decimal
nadezda [96]

Answer:

1?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If f(x) = 3x²+2 and g(x)=x2-9, find (f- g)(x).
Solnce55 [7]

Answer:

Step-by-step explanation:

Depending on whether or not the g(x) is x^2 or 2x, I have both ways.

If g(x) is x^2 - 9...

--> (3x^2 + 2) - (x^2 - 9) = 2x^2 + 11

If g(x) is 2x...

--> (3x^2 + 2) - (2x - 9) = 3x^2 - 2x + 11

Hope this helps!

4 0
2 years ago
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