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a_sh-v [17]
3 years ago
8

How many ml of 0.100 m naoh are needed to neutralize 50.00 ml of a 0.150 m solution of ch3co2h, a monoprotic acid?

Chemistry
1 answer:
bearhunter [10]3 years ago
8 0
50ml = 50cm³ = 0,05dm³
C = n/V
n = 0,15 mol/dm³ × 0,05dm³
n = 0,0075 mol CH₃COOH
..............................
CH₃COOH + NaOH ----> CH₃COONa + H₂O
1 mol...............1 mol

1 mol CH₃COOH ------------1 mol NaOH
0,0075 mol CH₃COOH --- X
X = 0,0075 mol NaOH

V = n/C
V = 0,0075/0,1
V = 0,075 dm³ = 75cm³ = 75 mL
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