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Ghella [55]
3 years ago
10

Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.

The median lethal dose of KCN for a person weighing 135 lb (61.2 kg ) is 5.74×10−3 mol . What volume of a 0.0640 M KCN solution contains 5.74×10−3 mol of KCN? Express the volume to three significant figures and include the appropriate units.
Chemistry
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

The volume will be 89.6875 ml

Explanation:

So to count this we will use a single proportion.

0.0640 mol - 1000 ml

5.74×10−3 mol - x ml

x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml

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Why do some elements form double and triple bonds during bonding
jekas [21]

Explanation:

Elements need a total of eight electrons to gain stability and look like a noble gas. So, they sometimes need sharing of two, four or even six electrons to complete their octate. So, they form double and triple covalent bonds. One more  the reason is the  interaction between the p orbitals of the combining atoms. for example  A double bond, as in ethene H2C=CH2, arises from one combination of the s orbitals and one combination of the p_y orbitals.

4 0
3 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
3 years ago
Please help!
valkas [14]
The answer is B . Brønsted-Lowry Acid/bases trade H+
3 0
3 years ago
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
3 years ago
A reduction reaction involves either the addition of hydrogen or removal of:
Marina CMI [18]

Reduction involves the either the addition of hydrogen and removal of oxygen.

<h3>What is reduction?</h3>

Reduction involves the removal of oxygen.

This implies there is a loss of oxygen in reduction.

This can be represented in the extraction of iron from it ores.

Fe₂O₃ + 3CO →  2Fe + 3CO₂

Reduction is also the addition of hydrogen. This implies it is the gain of hydrogen.

For example

CH₃CHO → CH₃CH₂OH

learn more on reduction here: brainly.com/question/9485345

#SPJ12

4 0
2 years ago
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